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An organic compound 'A' having molecular formula C_(2)H_(6)O evolves hydrogen gas on treatment with sodium metaland on treatment with red phosphorous and iodine gives compound 'B'. The compound 'B' on treatment with alcoholic KCN and on subsequentreduction gives compound 'C'. The compound 'C' on treatment with nitrousacid evolves nitrogen gas. Write the balanced chemical equationsfor all the reactions involved and identify the compounds 'A', 'B' and 'C'. |
Answer» Solution : (1) `underset((A))(2C_(2)H_(5)OH)+Na rarr underset("SODIUM ethoxide")(2C_(2)H_(5)ONa + H_(2))` `underset((A))(3C_(2)H_(5)OH + PI_(3)) overset(2P + 3I_(2))underset("in situ")rarrunderset((B))underset("ethyl iodide")(3C_(2)H_(5)I + H_(3)PO_(3))` (3) `underset((B))(C_(2)H_(5)I + KCN overset("alcohol")underset(Delta_(-KI))rarrunderset("ethyl nitrite")(C_(2)H_(5)CN) +4(H) overset("Na"/C_(2)H_(5)OH)rarrunderset((C))underset("n-propyl amine")(C_(2)H_(5)CH_(2)NH_(2))` (4) `underset("n-propyl amine")(C_(2)H_(5)CH_(2)NH_(2)) +HNO_(2) rarr underset("propan-1-ol")(C_(2)H_(5)CH_(2)OH) + N_(2) darr + H_(2)O` `A = C_(2)H_(5)OH` ethanol `B = C_(2)H_(5)I` ethyl iodide. `C = C_(2)H_(5)CH_(2)NH_(2)` n-propyl amine Compound `C_(2)H_(6)O = C_(2)H_(5)OH` |
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