An organic compound (A) has 76.6% C and 6.38% H. its vapour density is 47. it gives characteristic colour with FeCl_(3) solution. (A) when treated with CO_(2) and NaOH at 140^(@) C under pressure gives (B) which on being acidified gives (C). (C) reacts with acetyl chloride to give (D) which is a well known pain killer. identify (A), (B), (C), (D) and explain the reactions involved.

An organic compound (A) has 76.6% C and 6.38% H. its vapour density is

1.	An organic compound (A) has 76.6% C and 6.38% H. its vapour density is 47. it gives characteristic colour with FeCl_(3) solution. (A) when treated with CO_(2) and NaOH at 140^(@) C under pressure gives (B) which on being acidified gives (C). (C) reacts with acetyl chloride to give (D) which is a well known pain killer. identify (A), (B), (C), (D) and explain the reactions involved.
Answer» Solution :`{:("Atomic weight",,"Atomic ratio"),(C=76.6,=76.6//12,=6.38~~6),(H=6.38,=6.38//1,=6.38~~6):}` `O=100-(76.6+6.38)=17.02//16=1.06~~1` Emperical formula `=C_(6)H_(6)O` Emperical formula weight=94 Molecular weight=`V.d.xx2=47xx2=94` So, molecular formula=`C_(6)H_(6)O` Since (A) gives characteristic COLOUR with AQUEOUS `FeCl_(3)`. So it must be a phenolic compound and the formula of (A) may be