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An organic compound (A) contains 40% carbon 6.7% hydrogen and rest, oxygen. Its vapour density is 15. On reacting with a concentrated solution of KOH, it gives two compounds, (B) and (C ). When (B) is oxidised, the original compound (A) is obtained. When (C ) is treated with concentrated HCl, it gives a compound (D) which reduces Fehling's solution as well as ammoniacal AgNO_(3) solution and also gives effervescence with NaHCO_(3) solution. Write the structures of (A), (B), (C ) and (D) |
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Answer» Solution :Moles of `C: H: O` in `(A)= (40)/(12): (6.7)/(1): (53.3)/(16)` `=3.33: 6.7: 3.33` `=1: 2: 1` Empirical formula of (A) is `CH_(2)O` (30) As molecular WEIGHT of (A) is also equal to 30 (i.e., `2 xx VD`), molecular formula of (A) is `CH_(2)O`. Now from the FOLLOWING reaction sequence `{:((A),overset(KOH)rarr,(B),+,(C )),((CH_(2)O),,darr(O),,darrHCl),(,,(A),,(D)),(,,(CH_(2)O),,"reduces Fehling.s solution and AMM"),(,,,,AgNO_(3) "and gives effervescence with"NaHCO_(3)):}` It is clear that, (A) is HCHO (B) is `CH_(3)OH` ( C) is HCOOK and (D) is HCOOH |
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