1.

An organic compound (A) C_(6)H_(12)O_(3) on treatment with concentrated H_(2)SO_(4) gives CO, H_(2)O and (B). Compound (B) can be prepared by passing vapours of 1-pentanol Over heated copper at 570 K. Compound (A) on heating gives (C), C_(12)H_(20)O_(4). Give the structures of (A) to ( C) with proper reasoning.

Answer»

Solution :Compound (B) MUST be pentanol because 1t is PREPARED by passmg vapours of 1-pentanol over HEATED copper
`underset("Pentan -1-ol ")(CH_(3)(CH_(2))_(3)CH_(2)OH)underset(570 K)overset(Cu)tounderset("Pentanal")(CH_(3)(CH_(2))_(3)-CHO+H_(2)O)`
Compound (A) gives `CO_(2)` and `H_(2)O` on treatment with conc. `H_(2)SO_(4)`. Thus, compound (A) must be`alpha` -hydroxy acid


Discussion

No Comment Found