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An organic compound (A) C_(2)H_(6)O liberates hydrogen on treatment with metallic sodium. (A) on mid oxidation gives (B) C_(2)H_(4)O which answers iodoform test. (B) treated with conc. H_(2)SO_(4) undergoes polymerisation to give (C ), a cyclic compound. Identify (A), (B) and(C) and explain the reactions. |
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Answer» Solution :(i) `2CH_(2)H_(5)OH + 2Na to 2C_(2)H_(5)Ona + H_(2) darr` (ii) ETHYL alcohol on MILD oxidation gives acetaldehyde (B) it answers iodoform TEST. `CH_(3)-underset(A)(CH_(2)OH) overset("Mild"(O)) to underset((B))(CH_(3)CHO + H_(2)O)` `underset(B)(CH_(3)-CHO + 3I_(2)) + NaOH overset(B)underset("Iodoform") to CHI_(3) + HCOONa + 3HI` (iii) Acetaldehyde when treated with Conc. `H_(2)SO_(4)` undergoes polymerisation and the product obtained is paraldehyde (C). `underset((B)) (3CH_(3)CHO overset("conc"H_(2)SO_(4)) to`
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