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An ore contains 1.34% of the mineral argentile. Ag2s, by weight. How many gram of this ore would have to be processed in order to obtain 1.00g of pure silver. (Ag)-(A) 74.6g(B) 85.7g(C) 107.9g(D) 134.Og |
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Answer» Option B => 85.7 gExplanation:MOLAR mass of AG2S : => 108 x 2 + 32 = 248 g/molMass of silver in 1 mole of Ag2S : => 108 x 2 = 216g216 g of AG is contained in 248g of Ag2S1 g of Ag is consists in = => 1.148 g of Ag2SThe ore consists 1.34% Ag2S∴ 1.34% ≡ 1.148 g100% : 100% ≡ => 85.7 g. |
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