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An orbit electron in the ground state of hydrogen has an angular momentum `L_(1)`, and an orbital electron in the first orbit in the ground state of lithium (dounle ionised positively) has an angular momentum `L_(2)`. Then :A. `L_(1) = L_(2)`B. `L_(1) = 3 L_(2)`C. `L_(2) = 3L_(1)`D. `L_(2) = 9 L_(1)` |
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Answer» Correct Answer - A Doubly ionised positively lithium ion is a hydrogen like atom. hence : `L = m v r = (nh)/(2 pi)` for both which depends only on the value of n Also for both n = 1 Hence , `L_(1) = L_(2) = (h)/(2 pi)` , Hence (1). |
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