1.

An optical active alcohol of formula C_(4)H_(10)O on oxidation given which of the following compound?

Answer»

`(CH_(3))_(2)CHCHO`
`(CH_(3))_(2)C=CH_(2)`
`CH_(3)COC_(2)H_(5)`
`CH_(3)CH_(2)CH_(2)CHO`

SOLUTION :Molecular formula `C_(4)H_(10)O` has FOUR isomers i.e. n - BUTYL alcohol, ISOBUTYL alcohol , sec.
butyl alcohol, t-butyl and on oxidation gives ethyl methyl ketone.
`CH_(3)CHOHC_(2)H_(5) overset("oxidation") to CH_(3)COC_(2)H_(5) + H_(2)O`


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