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An open vessel contains 200 mg of air at 170 C.What weight percentage of air would be expelled if the vessel is heated to 1170 C? |
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Answer» Suppose vol. of 200 mg of air at 170 C =V mL Apply Charle’s Law V1/ T1=V2/ T2 V1/ 290 = V2/390 V2 =1.34 V1 , volume of air expelled = 1.34V1 –V1 =o.34V1 mL % of air expelled: 0.34V1x 100 /V1 = 34% |
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