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An observer moves towards a stationary source of sound with a velocity one-fifth of the velocity of sound. Calculate the percentage increase in the apparent frequency? |
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Answer» Solution :Here observer moves towards the stationary source. `:.v_(0)=-(v)/(5),v_(s)=0` Apparent frequency, `v'=(v-v_(0))/(v-v_(s))xxv=(v+(v)/(5))/(v-0)xxv=(6)/(5)v=1.2v`. The PERCENTAGE INCREASE in apparent frequency, `(v'-v)/(v)XX100=(1.2v-v)/(v)xx100` `=(0.2v)/(v)xx100=20%`. |
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