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An object travels `16 m` in `4 s` and then another `16 m` in `2 s`. What is the average speed of the object? |
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Answer» Correct Answer - `5.33 m//s` Here , `s_(1) = 16 m , t_(1) = 4 s` , `s_(2) = 16 m , t_(2) = 2 s` Average speed `= ( "total distance travelled")/( "total time taken ")` `v_(av) = ( s_(1) + s_(2))/( t_(1) + t_(2)) = (( 16 + 16) m)/(( 4 + 2) s) =(32)/(6) = 5.33 m//s` |
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