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An object starts from rest and achieves a velocity of 4 m/s in with a acceleration motion. what distance it has covered after 6 second.[Hint - first calculate acceleratook and then use 2nd equation of motion to calculate second. ] |
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Answer» Answer: 12m Explanation: USING 1st eq. of motion, v=u+at 4m/s = 0 + a*6s a = 4/6 m/s² now using 2ND eq. of motion, s = UT + 1/2at² s = 0*6+1/2(4/6*(6)²) s=1/2(4*6) s= 1/2*24 s= 12M. answer |
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