An object of size 7cm is placed at 27cm in front of a concave mirror o

1.	An object of size 7cm is placed at 27cm in front of a concave mirror of focal length 18cm. At what distance from the mirror should a screen be placed so that a sharp focused image can be obtained? Find the size and nature of image.
Answer» Given:- Object height ,HO = 7cm Object distance ,u = -27cm Focal Length ,f = -18cm To Calculate:- IMAGE distance ,v size and nature of image . Solution:- By using mirror formula → 1/v + 1/u = 1/f Substitute the value we get → 1/v + 1/(-27) = 1/(-18) → 1/v = 1/(-18) - 1/(-27) → 1/v = -1/18 + 1/27 → 1/v = -3+2 /54 → 1/v = -1/54 → v = -54 cm ∴The image distance is -54cm. Now → MAGNIFICATION ,m = hi/ho = -v/u Substitute the value we get → hi/7 = - (-54)/(-27) → hi/7 = -54/27 → hi = -7×2 → hi = -14cm ∴ The height of the image is -14 cm. The image formed is real and inverted .

An object of size 7cm is placed at 27cm in front of a concave mirror of focal length 18cm. At what distance from the mirror should a screen be placed so that a sharp focused image can be obtained? Find the size and nature of image.

Answer»

Given:-

Object height ,HO = 7cm

Object distance ,u = -27cm

Focal Length ,f = -18cm

To Calculate:-

IMAGE distance ,v
size and nature of image .

Solution:-

By using mirror formula

→ 1/v + 1/u = 1/f

Substitute the value we get

→ 1/v + 1/(-27) = 1/(-18)

→ 1/v = 1/(-18) - 1/(-27)

→ 1/v = -1/18 + 1/27

→ 1/v = -3+2 /54

→ 1/v = -1/54

→ v = -54 cm

∴The image distance is -54cm.

Now

→ MAGNIFICATION ,m = hi/ho = -v/u

Substitute the value we get

→ hi/7 = - (-54)/(-27)

→ hi/7 = -54/27

→ hi = -7×2

→ hi = -14cm

∴ The height of the image is -14 cm.

The image formed is real and inverted .

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An object of size 7cm is placed at 27cm in front of a concave mirror of focal length 18cm. At what distance from the mirror should a screen be placed so that a sharp focused image can be obtained? Find the size and nature of image.​