1.

an object of mass 500 gram is dropped from a tower of height 5m calculate its Momentum when it touches the ground given the is equal to 10 M per second square

Answer»

V²=u²+2as
u=0
s=5m
a=10m/s²
v²= 0+2(10)(5)
v²= 100
v= 10m/s

momentum = MASS × velocity
m=500g
m=0.5KG
p=0.5×10
p= 5kg m/s



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