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An object of mass 5 kg is moving with a velocity of 10 ms-1 . A force is applied so that in 15 s, it attains a velocity of 25 ms-1 . What is the force applied on the object? |
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Answer» Mass (m) = 5 kg ; Initial velocity (u) = 10 m/s.; Time (t) = 15 s Final velocity (v) = 25 m/s. Acceleration a = \(\frac{v\,-\,u}{t}=\frac{25\,-\,10}{15}=\frac{15}{15}=1\,m/s^2.\) Force applied on the object F = ma = 5 × 1=5 N. |
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