An object of mass 3 kg is at rest. Now a force of vecF=6t^(2)hati+4thatj is applied on the object, then the velocity of object at t=3 second is

An object of mass 3 kg is at rest. Now a force of vecF=6t^(2)hati+4tha

1.	An object of mass 3 kg is at rest. Now a force of vecF=6t^(2)hati+4thatj is applied on the object, then the velocity of object at t=3 second is
Answer» `18hati+3hatj` `18hati+6hatj` `3hati+18hatj` `18hati+4hatj` SOLUTION :`F=6T^(2)hati+4thatj` `F=ma"":.a=(BARF)/(m)=(1)/(3)(6t^(2)hati+4thatj)=2T^(2)hati+(4)/(3)thatj` `a=(dV)/(dt)"":.v=int_(0)^(t)adt=int_(0)^(3)2t^(2)hatjdt+int_(0)^(3)(4)/(5)thatjdt=18hati+6hatj`