Saved Bookmarks
| 1. |
An object of mass 10kg placed on the smooth horizontal table initially at rest. Now 10N constant forces acting in the body. The displacement of the object after 5sec |
|
Answer» hat, an object of mass 10kg placed on the smooth horizontal table initially at rest. ALSO, a force of 10N acts on object.W have to find the displacement of the object after 5sec.From above data we have, mass (m) = 10 kg, force (F) = 10N and time (t) = 5 secForce is defined as the product of mass and acceleration. i.e.F = maSubstitute the known values in the above formula,10 = 10aDivide by 10 on both sides,10/10 = 10a/101 = aTherefore, the acceleration is 1 m/s². But we have to find the displacement (s) of the object.Using the Third Equation Of MOTION,s = UT + 1/2 at²Initial velocity of the object is 0 m/s because initially object is at rest.s = 0(5) + 1/2 × 1 × (5)²s = 0 + 1/2 × 25s = 25/2s = 12.5Therefore, the displacement of the object is 12.5 m. |
|