1.

An object of mass 10kg is dropped from a height of 100 cm. find:a) its kinetic energyb)velocity just as it reaches the ground (g=10m/s2)

Answer» mass of the OBJECT ( m ) = 10 kg
  height (h) = 100cm = 1m
  g = 10m/s
\frac{<klux>1</klux>}{2} mv^2K.E.= 
  
when the body REACHES the ground its P.E. changes into K.E.
object on the top = K.E.on the ground 
 mgh = K.E.on the ground 
\frac{1}{2} v^2 gh= 
\sqrt{2gh} v = 
\sqrt{2*10*1}v = 
\sqrt{20}v =   m/s

 P.E = mgh
     = 10 * 10 * 1
     = 20 j
 




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