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An object of mass 10kg is dropped for a height 100 cm find kinectic energy and welocity before as it reaches the ground |
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Answer» 10kgheight = 100CM = 1 mKE = PE = MGH = 10×9.8×1 = 98 JKE = 98 J=> 1/2 mv^2 = 98=> v^2 = 98×2 / 10=> v^2 = 19.6 => v = √19.6 m/s=> v = 4.4 m/sKinetic ENERGY is 98J and velocity is 4.4 m/s |
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