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An object of mass 10 kg moving with a speed of 15 ms- hits the wall and comes to res within (a) 0.03 second (b) 10 second. Calculate the impulse and average force acting on the object in both the cases |
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Answer» <P> Solution :Initial momentum of the OBJECT `P_i= 10 xx 15= 150 kg ms^(-1)`Final momentum of the object `P_f = 0` `Delta P = 150 - 0 = 150 kg MG^(-1)` (a) Impulse J= `DeltaP` = 150 N s and Average force `F_(avg) = (Delta P)/(Delta t) = (150)/(0.03) = 5000 N` (B) Impulse`J = Delta P = 150 N ` s and average force `F_(avg) = 150/10 = 15N` We see that, impulse is the same in both CASES, but the average force is different. |
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