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an object of mass 0.5 kg is held at end of a string 0.8 long if the string makes three revolution in 1.2 second find the tension of a string​

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we \ have \ to \ find \ tension\\\\Let \ us \ do\\\\t=\frac{1.2}{3}=0.4 sec\\\\v=\frac{2\pi r }{t}=\frac{2\pi 0.8 }{0.4}=4\pi \\\\we \ know \ tension \ equals \ to\\\\T=\frac{mv^{2} }{r} =\frac{0.5 \times4\pi \times 4\pi }{0.8}=98.7N\\

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