An object of mass 0.2 kg executes simple harmonic oscillations along the x-axis with a frequency (25)/(pi)Hz. At position x = 0.04m, the object has kinctic cnergy 0.5J and (potential energy is zero at mean position) Find its amplitude of vibration.

An object of mass 0.2 kg executes simple harmonic oscillations along t

1.	An object of mass 0.2 kg executes simple harmonic oscillations along the x-axis with a frequency (25)/(pi)Hz. At position x = 0.04m, the object has kinctic cnergy 0.5J and (potential energy is zero at mean position) Find its amplitude of vibration.
Answer» SOLUTION :`omega= 2pif= sqrt((k)/(m)) :. K= (2pif)^(2)m` Total energy of OSCILLATION is (0.5+0.4) = 0.9J `:. 0.9 =(1)/(2)KA^(2)` or `A- sqrt((1.8)/(k))= sqrt((1.8)/((2pif)^(2)m))= (1)/(2pif)sqrt((1.8)/(0.2))= (1)/(2PI((25)/(pi)))sqrt((1.8)/(0.2))= (3)/(50) m= 6cm `