An object of length 10 cm is place at right angles to the principal axis of a mirror of radius of curvature 60 cm such that its image is virtual, erert and has a length 6 cm. What kind of mirror is it and also determine the positions of the object.

An object of length 10 cm is place at right angles to the principal ax

1.	An object of length 10 cm is place at right angles to the principal axis of a mirror of radius of curvature 60 cm such that its image is virtual, erert and has a length 6 cm. What kind of mirror is it and also determine the positions of the object.
Answer» Solution :Since the image is virtual, erect and of a smaller size, the given MIRROR is convex (concave mirror does not form an image with the said DESCRIPTION) Given R=+60 cm `f=R/2=30 cm` Transverse magnification `m=I/O=6/10= pm3/5` Further `m=-v/u =3/5 therefore v=- (3u)/5` Using `1/v+1/u=1/f (-5)/(3u)+1/u= 1/30` `(-5+3)/(3u)=1/30 therefore u=-20 cm` THUS the object is at a distance 20 cm (from the pole) in front of the mirror).