An object of height h_(0)=1 cm is moved along principal axis of a convex lens of focal length f=10 cm. Figure shows variation of magnitudeof height of image with image distance (v) . Find v_(2)-v_(1) in cm .

An object of height h_(0)=1 cm is moved along principal axis of a conv

1.	An object of height h_(0)=1 cm is moved along principal axis of a convex lens of focal length f=10 cm. Figure shows variation of magnitudeof height of image with image distance (v) . Find v_(2)-v_(1) in cm .
Answer» Solution :`(h_(i))/(h_(0))=(f-v)/(f) rArrh_(i)=-(v)/(f)h_(0)+h_(0)RARR \|h_(i)\|=-(v)/(f)h_(0)+h_(0)-inftylevlef` `\|h_(i)\|=(v)/(f)h_(0)-h_(0)flevle-infty` So `h_(2)=h_(2)=1 cm` From second eq. `v_(2)=2f` Or When `vrarr0,urarr0&h_(i)rarrh_(0)soh_(2)=h_(0)=1 cm` image of same height is obtained when `v=2f` so `v_(2)=2f`

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An object of height h_(0)=1 cm is moved along principal axis of a convex lens of focal length f=10 cm. Figure shows variation of magnitudeof height of image with image distance (v) . Find v_(2)-v_(1) in cm .

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