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An object of height 1.5 m is placed at a distance of 15 cm from a concave mirror of focal length 30 cm so that a virtual image is formed. Calculate position, nature and size of the image. Draw a ray diagram to show the image formation in the above case |
| Answer» TION:CORRECT option isA−10 cmGiven,object height h1=1.5 cmreal IMAGE length h2=−3cmPosition of object from the mirror u=−15cmMirror MAGNIFICATION formulam=h1h2=−uv1.5−3=−15−vv=−30cmApply Mirror formulaf1=−301+−151f=−10cm i hope help you! | |