1.

An object moves 6 km due west and then 8 km duemorth. Find the distance covered by the object and its displacement.​

Answer»

Solution :

★ Displacement -

Displacement is the shortest distance from the origin to the final point. According to the QUESTION, (refer the attachment) AC FORMS the shortest distance.

By Pythagoras THEOREM,

In ∆ ABC,

>> HYPOTENUSE = CA = y

>> Height = BC = 8 km

>> Base = BA = 6 km

\bigstar \: {\boxed{\sf{(Hypotenuse)^{2} = (Base)^{2} + (Height)^{2}}}}

⇒ (y)² = (6)² + (8)²

⇒ y² = 36 + 64

⇒ y² = 100

⇒ y = √100

⇒ y = 10

CA = 10 km

Shortest distance = 10 km

Therefore, the displacement is 10 km.

\rule{300}{1.5}

★ Distance -

⇒ 8km + 6km

⇒ 14 km

Therefore, the distance covered is 14 km.


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