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an object is thrown upwards in the vertical direction to a height of 10 mts calculate its velocity with what it is thrown and time taken to reach maximum height (g=9.8m\s²) |
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Answer» Explanation:Given :Height (h) = 10 mFinal velocity (v) = 0 m/sAcceleration due to gravity (g) = -9.8 m/s²To FIND :It's velocity & Time taken to reach MAXIMUM height. Solution :We KNOW,Height = Distance => 10 m = Distance => Distance = 10 mApplying 3rd equation of motion,v² = u² + 2gs=> 0² = u² + 2 × -9.8 × 10=> -u² = -196=> u² = 196=> u = 14 m/sApplying 1ST equation of motion,v = u + at=> 0 = 14 + -9.8 × t=> -14 = -9.8t=> 14 = 9.8t=> t = 14/9.8=> t = 1.43 sHence :It's velocity & Time taken to reach maximum height is 1.43 s. |
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