1.

An object is thrown up with a speed of 50m/s. Its height from the ground after 7s is

Answer»

S=ut+1/2(at^2)
s=50*7 + (1\2)(-10*49)   (ACCELEARTION due to GRAVITY is in opposite DIRECTION to                                            DISPLACEMENT .thus a is -ve) 
s=350-5*49
s=350-245
s=105 m



Discussion

No Comment Found

Related InterviewSolutions