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An object is projected with a velocity of `20(m)/(s)` making an angle of `45^@` with horizontal. The equation for the trajectory is `h=Ax-Bx^2` where h is height, x is horizontal distance, A and B are constants. The ratio A:B is (g`=ms^-2)`A. `1:5`B. `5:1`C. `1:40`D. `40:1` |
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Answer» Correct Answer - D Standard equation of projectile motion `y = x tan theta - (gx^(2))/(2u^(2) cos^(2)theta)` Comparing with given equation `A = tan theta` and `B = (g)/(2u^(2) cos^(2) theta)` So, `(A)/(B) = (tan theta xx 2u^(2) cos^(2) theta)/(g) = 40` (As, `theta = 45^(@), u = 20 ms^(-1), g = 10 ms^(-2))` |
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