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An object is placed on the principal axis of a concave mirror of focal length 10cm at a distance of 8.0 cm from the pole then the position and nature of the image a) 40 cm real b) 40 cm virtualc) 20 cm reald) 20 cm virtual |
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Answer» Light incident from particle P will be reflected at mirroru=−5cm,f=− 2R =−20cmv1 + u1 = f1 v 1 =+ 320 cm This image will ACT as OBJECT for light getting refracted at water surfaceSo, object distance d=5+ 320 = 335 cmbelow water surface,After refraction, final image is ATD ′ =d( μ 1 μ 2 )=( 335 )( 4/31 )= 435 =8.75cm≈8.8cm |
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