An object is placed at a distance of 8 cm form a convex mirror of foca

1.	An object is placed at a distance of 8 cm form a convex mirror of focal length 12 cm. Find the position of the image formed?
Answer» According to the question; Focal length (f) = 12cm; Object distance (u) = -8cm; By mirror formula; \(\frac1v\,+\,\frac1u\,=\,\frac1f\) ⇒ \(\frac1v\,+\,\frac1{-8}\,=\,\frac1{12}\) ⇒ \(\frac1v\,+\,\frac1{8}\,=\,\frac1{12}\) \(\frac1v\,=\,\frac{3+2}{24}\) ⇒ \(\frac1v\,=\,\frac{5}{24}\) ⇒ v = \(\frac{5}{24}\) = 4.8 cm. Since v = 4.8cm which is positive hence image is behind the mirror. The image is formed at the distance of 4.8 cm behind the mirror and is virtual and erect.

An object is placed at a distance of 8 cm form a convex mirror of focal length 12 cm. Find the position of the image formed?

Answer»

According to the question;

Focal length (f) = 12cm;

Object distance (u) = -8cm;

By mirror formula;

\(\frac1v\,+\,\frac1u\,=\,\frac1f\)

⇒ \(\frac1v\,+\,\frac1{-8}\,=\,\frac1{12}\)

⇒ \(\frac1v\,+\,\frac1{8}\,=\,\frac1{12}\)

\(\frac1v\,=\,\frac{3+2}{24}\)

⇒ \(\frac1v\,=\,\frac{5}{24}\)

⇒ v = \(\frac{5}{24}\) = 4.8 cm.

Since v = 4.8cm which is positive hence image is behind the mirror.

The image is formed at the distance of 4.8 cm behind the mirror and is virtual and erect.