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An object is placed at a distance of 4cm from a concave lens of focal length 12cm. Find the position and nature of the image |
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Answer» u = -4 cm f = -12 cm Lens formula : 1/v – 1/u = 1/f 1/v – 1/-4 = 1/-12 1/v = - (1/12 ) – 1/4 1/v = -4/12 V = - 3cm Image is formed 3 cm infront of the concave lens. Image is virtual and erect. |
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