1.

An object is placed at a distance of 4cm from a concave lens of focal length 12cm. Find the position and nature of the image

Answer»

u = -4 cm

f = -12 cm

Lens formula : 1/v – 1/u = 1/f

1/v – 1/-4 = 1/-12

1/v = - (1/12 ) – 1/4

1/v = -4/12

V = - 3cm

Image is formed 3 cm infront of the concave lens.

Image is virtual and erect.



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