An object is placed at a distance of 10cm from a concave mirror of foc

1.	An object is placed at a distance of 10cm from a concave mirror of focal length 5cm. find the nature and position of image?
Answer» Step-by-step explanation: Object Distance ,u = -10 cm Focal length ,f = -5 cm To Find:- Nature & Position of Image Solution:- As we have to calculate the nature and position of Image. Using mirror formula • 1/v + 1/u = 1/f where , v is the Image Position u is the object distance f is the focal length Substitute the value we get → 1/v = 1/f - 1/u → 1/v = 1/-5 - 1/-10 → 1/v = -1/5 + 1/10 → 1/v = -2+1/10 → 1/v = -1/10 → v = -10 cm Hence, the image position is on the CENTER of Curvature and the image distance is 10 cm left from the pole. Now, calculating the magnification • m = -v/u substitute the value we get → m = -(-10)/-10 → m = 10/-10 → m = -10/10 → m = -1 Here , negative SIGN show that the image formed is REAL & inverted and as the same size as the object .

An object is placed at a distance of 10cm from a concave mirror of focal length 5cm. find the nature and position of image?

Answer»

Step-by-step explanation:

To Find:-

Solution:-

As we have to calculate the nature and position of Image. Using mirror formula

where ,

Substitute the value we get

→ 1/v = 1/f - 1/u

→ 1/v = 1/-5 - 1/-10

→ 1/v = -1/5 + 1/10

→ 1/v = -2+1/10

→ 1/v = -1/10

→ v = -10 cm

Hence, the image position is on the CENTER of Curvature and the image distance is 10 cm left from the pole.

Now, calculating the magnification

• m = -v/u

substitute the value we get

→ m = -(-10)/-10

→ m = 10/-10

→ m = -10/10

→ m = -1

Here , negative SIGN show that the image formed is REAL & inverted and as the same size as the object .