1.

An object is placed 8 cm away in front of a concave mirror of focal length 5 cm. Find out the position of image and magnification. Find out whether the image is inverted or erect by drawing the ray diagram on a graph paper.

Answer»

f = – 5 cm, u = – 8 cm

-5 = \(\cfrac{-8v}{-8+v}\)

-5 (-8 +v) = -8v

40-5v = -8v

40 = -3v

\(\therefore\) 3v = -40

v = -40/3 = -13.34 cm

Features of images : Beyond C, big, real, inverted

Magnification m = \(\cfrac{h_i}{h_o} = \cfrac{-v}{u}\)

m = \(\cfrac{-v}{u}\) = (-13.34/-8) = -16.7



Discussion

No Comment Found

Related InterviewSolutions