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An object is placed 8 cm away in front of a concave mirror of focal length 5 cm. Find out the position of image and magnification. Find out whether the image is inverted or erect by drawing the ray diagram on a graph paper. |
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Answer» f = – 5 cm, u = – 8 cm -5 = \(\cfrac{-8v}{-8+v}\) -5 (-8 +v) = -8v 40-5v = -8v 40 = -3v \(\therefore\) 3v = -40 v = -40/3 = -13.34 cm Features of images : Beyond C, big, real, inverted Magnification m = \(\cfrac{h_i}{h_o} = \cfrac{-v}{u}\) m = \(\cfrac{-v}{u}\) = (-13.34/-8) = -16.7 |
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