1.

an object is moving up with a velocity V if the velocity of this rocket is suddenly double what will be the ratio of two kinetic energies​

Answer»

1:9Explanation:Initial velocity =v, then v =3v (TRIPLED Velocity)Initial KINETIC energy = 21 MV 2 FINAL kinetic energy (K.E.)= 21mv ′2 = 21 m(3v) 2=9( 21mv2 )∴ (K.E.) initial:(K.E.) ffina=21mv 2:9( 21mv 2)=1:9



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