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An object having a mass 'm' moving with velocity 'v' possess a kinetic energy 'k'.if its velocity is doubled, it's kinetic energy will become

Answer»

Answer: ...will become 4 TIMES

Explanation:

Let the INITIAL KINETIC energy be k_1 and the final kinetic energy for twice the VELOCITY be k_2

Here velocity(v) is doubled so it BECAME 2v.

k_1=\frac{1}{2} mv^{2}

Putting 2v instead of v will represent the velocity is doubled.

k_2=\frac{1}{2} m(2v)^{2} \\k_2=\frac{1}{2} m*4v^{2} \\k_2=4*\frac{1}{2} mv^{2} \\k_2=4*k_1

Now we can clearly see that if the velocity become twice its original value, the final kinetic energy will become 4 times the original.


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