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An object 5 cm high is placed at a distance of 30 cm from a convex lens of a focal length 15 cm . Find the position and nature |
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Answer» Given:- Height of Object, Ho = 5cm Distance of the Object, u = -30cm Focal length , f = +15cm Now, \(\frac{1}{v} - \frac{1}{u} = \frac{1}{f}\) \(\frac{1}{v} = \frac{1}{f} + \frac{1}{u}\) \(\frac{1}{v} = \frac{1}{15} - \frac{1}{30} = \frac{1}{30}\) \(v = 30cm\) (i) The image is formed at a distance of 30cm from the lens to its right side. (ii) Magnification, m = \(\frac{v}{u} = \frac{30}{-30}\) \(= -1\) The image formed is real, inverted and of the same size as that of object. |
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