An object 2cm tall is placed in front of a concave mirror of radius of

1.	An object 2cm tall is placed in front of a concave mirror of radius of curvature 20cm at a distance of 5cm. Find the position, nature and size of the image.
Answer» <U>According to the QUESTION It is given that, Height of object ,ho = 2cm Radius of Curvature ,R = 20cm Object distance ,u = -5cm Type of Mirror = Concave Mirror we have to calculate the position , nature and size of the mirror . Firstly we calculate the focal length of the mirror. f = R/2 ➻ f = 20/2 CM ➻ f = 10cm Now, calculating the image distance . By using Mirror Formula . 1/v + 1/u = 1/f Substitute the value we get ➻ 1/v + 1/-5 = 1/10 ➻ 1/v - 1/5 = 1/10 ➻ 1/v = 1/10 + 1/5 ➻ 1/v = 1+2/10 ➻ 1/v = 3/10 ➻ v = 10/3 = 3.33 cm Hence, the image distance is 10/3 cm from the mirror. Now, calculating the magnification of the mirror m = hi/ho = -v/u ➻ hi/2 = -10/3 × 1/-5 ➻ hi/2 = 2/3 ➻ hi = 4/3 cm Hence, the height of the image is 4/3 cm Nature of Image is Virtual , erect and smaller than the object.

An object 2cm tall is placed in front of a concave mirror of radius of curvature 20cm at a distance of 5cm. Find the position, nature and size of the image.

Answer»

<U>According to the QUESTION

It is given that,

we have to calculate the position , nature and size of the mirror .

Firstly we calculate the focal length of the mirror.

➻ f = 20/2 CM

➻ f = 10cm

Now, calculating the image distance .

By using Mirror Formula .

Substitute the value we get

➻ 1/v + 1/-5 = 1/10

➻ 1/v - 1/5 = 1/10

➻ 1/v = 1/10 + 1/5

➻ 1/v = 1+2/10

➻ 1/v = 3/10

➻ v = 10/3 = 3.33 cm

Hence, the image distance is 10/3 cm from the mirror.

Now, calculating the magnification of the mirror

➻ hi/2 = -10/3 × 1/-5

➻ hi/2 = 2/3

➻ hi = 4/3 cm

Hence, the height of the image is 4/3 cm
Nature of Image is Virtual , erect and smaller than the object.