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An LPG (liquefied petroleum gas) cylinder weighs 14.8 kg when empty. When full, it weighs 29.0 kg and shows a pressure of 2.5 atm. In the course of use at `27^(@)C`, the weight of the full cylinder reduced to 23.2 kg. Find out the volume of the cubic metres used up at the normal usage conditions, and the final pressure inside the cylinder. Assume LPG to be n-butane with normal boiling point of `0^(@)C` |
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Answer» Decrease in the amount of PG`=29.0-23.2=5.8" kg"=(5800)/(58)" kg moles"=100" moles"` Volume of 100 moles at 1 atm `300" K "(nRT)/(P)=(100" moles"xx0.0821" L atmK^(-1)xx300 K)/(1 atm)` `=2463" L "=2463xx10^(-3)m^(3)=2.463m^(3)` Final pressure inside the cylinder. As the cylinder contains liquefied petroleum gas in equibrium with its vapours, therefore, so long as temperature remains constant and some LPG is present, pressure with remain constant. As the cylinder still contains LPG=23.2-14.8=8.4 kg, pressure inside the cylinder will be same, i.e., 2.5 atm. |
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