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An isotope ._(Y)A^(X) undergoes a series of m alpha and n beta disintegrations to form a stable isotope ._(Y -10)B^(X -32). The value of m and n are respectively |
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Answer» 6 and 8 Value of `m = (X -(X) -32)/(4) = 8` Value of `n = Y - Y - 10 - 2 xx 8 = 6` |
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