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An iron sphere of mass 10 kg is dropped from a height of 80 cm, if ‘g’ = 10 m / s2. Calculate the momentum transferred to the ground by the body. |
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Answer» Here, initial velocity of sphere, u=0 Distance TRAVELLED, s=80cm=0.8m Acceleration of sphere, a=10ms−2 Final velocity of sphere when it just reaches the GROUND can be CALCULATED using v2−u2=2as ∴v2−0=2×10×0.8=16 or v=16=4ms−1. Momentum of the sphere just before it touches the ground =mv=10×4=40kgms−1 |
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