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An iron pipe 20 CM long has exterior diameter equal to 14 CM. If the thickness of the pipe is 1 cm,then find whole surface area of pipe. |
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Answer» Height=20 cm exterior DIAMETER= 14cm Therefore, exterior radius(R)=14/2=7. THICKNESS of Pipe= 1cm. Therefore Inner Radius (r)=R - Thickness 7-1=6 Assuming that top and BOTTOM are open, Whole surface AREA of Pipe= 2πh(R+r) + 2π (R^2-r^2) 2 x 22/7 (7+6) + 2 x 22/7 (7^2-6^2) =44/7 x 13 + 44/7 x 13 =81.71 x2 =163.428 |
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