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An iron ball of mass 0.2 kg is heated to 10 degree celsius and put into a block of ice at 0 degree celsius 25 gram of ice melts if latent heat of fusion of ice is 80 cal /g then specific heat of iron is |
Answer» specific heat of iron is 238.095 J/Kg/°CAn iron ball of mass , M = 0.2 kg is heated to 10°C and put into a block of ICE at 0°C, m = 25g of ice melts. heat absorbed by iron ball, Q = Ms∆T = 0.2 × s × 10 = 2s ........(1) heat gained by ice to melt it, Q' = mL_f = 25g × 80cal/g = 25 × 80 cal we KNOW, 1 cal = 4.2 Joule so, Q' = 25 × 80/4.2 = 476.19 J heat gained = heat lost ⇒Q = Q' ⇒2s = 476.19 J ⇒s = 476.19/2 = 238.095 J/Kg/°C also read similar questions : 540 grams of ice at zero degree celsius is mixed with 540 gram of water at 80 degree celsius the final temperature of th... 30g ice cube at 0 degree Celsius is dropped into 200g of water at 30 degree Celsius. CALCULATE the final temperature of ... |
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