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An ionic compound MCl is simultaneously doped with `10^(-6)` mole % `NCl_2` and `10^(-7)` mole % `RCl_3`.Calculate the concentration of cationic vacancies x. Express your answer as `x/9xx10^14`. (take N & R =divalent & trivalent cations) |
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Answer» Correct Answer - 8 Conc.of cationic vacancies `=10^(-6)xx6xx10^(23)+10^(-9)xx6xx10^(23)xx2=6xx10^(15)+12xx10^(14)=(60+12)xx10^14=72xx10^(14)` |
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