1.

An ionic compound MCl is simultaneously doped with `10^(-6)` mole % `NCl_2` and `10^(-7)` mole % `RCl_3`.Calculate the concentration of cationic vacancies x. Express your answer as `x/9xx10^14`. (take N & R =divalent & trivalent cations)

Answer» Correct Answer - 8
Conc.of cationic vacancies
`=10^(-6)xx6xx10^(23)+10^(-9)xx6xx10^(23)xx2=6xx10^(15)+12xx10^(14)=(60+12)xx10^14=72xx10^(14)`


Discussion

No Comment Found

Related InterviewSolutions