An ion with mass number 37 possesses unit negative charge. If the ion

1.	An ion with mass number 37 possesses unit negative charge. If the ion contains 11.1% more neutrons than electrons. Find the symbol of the ion.
Answer» Let the number of electrons in an ion = x number of neutrons = n = x + 11.1/100 eV = 1.111 x (As the number of neutrons are 11.1% more than the number of electrons) In the neutral of atom, number of electron. e^- = x – 1 (as the ion carries -1 charge) Similarly number of protons = P = x – 1 Number of protons + number of neutrons = mass number = 37 (x – 1) + 1.111 x = 37 . 2.111 x = 37 +1 2.111 x = 38 x = 38/2.111 = 18.009 = 18 ∴ Number of protons = atomic number – 1 = 18 -1 = 17 ∴ The symbol of the ion = . \(_{17}^{37}Cl\).

An ion with mass number 37 possesses unit negative charge. If the ion contains 11.1% more neutrons than electrons. Find the symbol of the ion.

Answer»

Let the number of electrons in an ion = x

number of neutrons = n = x + 11.1/100 eV = 1.111 x (As the number of neutrons are 11.1% more than the number of electrons)

In the neutral of atom, number of electron.

e^- = x – 1 (as the ion carries -1 charge)

Similarly number of protons = P = x – 1 Number of protons + number of neutrons = mass number = 37

(x – 1) + 1.111 x = 37 .

2.111 x = 37 +1

2.111 x = 38

x = 38/2.111

= 18.009 = 18

∴ Number of protons = atomic number – 1

= 18 -1

= 17

∴ The symbol of the ion = . \(_{17}^{37}Cl\).