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An insulated container containing monoatomic gas of molar mass m is moving with a velocity `V_(0)`. If the container is suddenly stopped , find the change in temperature .A. `(mv_(0)^(2))/(2R)`B. `(mv(0)^(2))/(3R)`C. `(R )/(mv_(0)^(2))`D. `(3mv_(0)^(2))/(2R)` |
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Answer» Correct Answer - B If the container is suddenly stopped loss in kinetic energy of gas `=1/2(mn)v_(0)^(2),` where n is number of moles of gas. Let `DeltaT` is the fall in temperature of gas, Then,`n((3)/(2)RDeltaT)=1/2mnv_(0)^(2)` `DeltaT=(mv_(0)^(2))/(3R)` |
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