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An infinte wire having linear charge density `lambda` is arranged as shown in fig. A charge particle of mass m and charge q is released charged q is released from point P. Find the initial acceleration of the particle just after the particle is released. |
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Answer» Correct Answer - `-(lambda)/(2 pi epsilon_(0)R)(-hat j)`. Electric field due to straight wires will cancel out. The net electric field will be due to semicircular wire only. Hence, `vecE_("net")=vecE_("circular")=(lambda)/(2 pi epsilon_(0)R)(-hat j)` so, acceleration is ` vec(a) = (q vecE_("net"))/(m)=(q lambda)/(2 pi epsilon_(0)mR)(hat j)`. |
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