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An infinite number of tangents can be drawn from `(1,2)`to the circle `x^2+y^2-2x-4y+lambda=0`. Then find the value of `lambda` |
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Answer» Correct Answer - 5 Clearly, the point (1,2) is the center of the given circle and infinite tanegents can only be drawn on a point circle. Hence, the radius should be 0. Therefore, `sqrt(1^(2)+2^(2)-lambda)=0` or `lambda =5` |
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