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An infinite number of particles each of mass m are placed on the positive x-axis at 1m, 2m, 4m, 8m,…. from the origin. The magnitude of the resultant gravitational force on mass 'm' kept at the origin is |
Answer» Solution : The resultant gravitational FORCE `F = (Gm^(2))/(1) + (Gm^(2))/(4) + (Gm^(2))/(16)+…..` `= Gm^(2)((1)/(1)+(1)/(4)+(1)/(16)+….) = Gm^(2)((1)/(1-(1)/(4)))` (`because` sum of the INFINIT TRMS in G.P is `S_(prop) = (a)/(1-r)`) `= (4)/(3)Gm^(2)` |
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