Saved Bookmarks
| 1. |
An infinite number of charges each q are placed in the x-axis distances of 1, 2,4,8...... meter from the origin. If the changes are allately positive and negative find the intensity of electric field at origin |
Answer» SOLUTION :The ELECTRIC field intensities due to POSITIVE charges at origin is away from the charges and due to -ve charges the field intensity is towards the charges  The resultant intensity at the origin `E = E_1 - E_2 + E_3 - E_4 `--------- `E = Q/(4 pi epsilon_0)(1 - 1/(2^2) + 1/(4^2) - 1/(8^2) + …...)` Since the expression in the bracket is in GP with a common ratio = `(-1)/(2^2) = (-1)/(4)` `E = Q/(4 pi epsilon_0) (1)/([1 - ((-1)/(4))]) = Q/(4 pi epsilon_0) cdot 4/5` `E = 4/5cdot Q/(4 pi epsilon_0) "" E = Q/(5PI epsilon_0)`. |
|